Re: SQL Question - Join Full example given
Matt S wrote:
> Yes, the objective is to get all of the clients
> information in one row (one row per client) using
> the address with the highest addressid and the
> count with the hightest countid. I actually have
> more joins, but if I get a working soltion for the
> above problem, I am pretty sure I can get things
> working.
Maybe of interest:
http://dev.mysql.com/doc/mysql/en/example-maximum-column-group-row.html
--
felix
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Re: SQL Question - Join Full example given
May 27, 2005 12:46PM
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