Re: How to define TOP 5 records?
Posted by:
Sergei
Date: June 16, 2005 04:28AM
When I tried do it in MySQL Query Browser it didn't work, but in SQLyog it runs well :)
I don't know that the reason was...
In Query Browser I could not excute all commands
DROP TABLE IF EXISTS temp_ttt;
CREATE TEMPORARY TABLE temp_ttt SELECT vote FROM ttt ORDER BY vote DESC LIMIT 5;
SELECT ttt.uid, ttt.uname Best, ttt.vote
FROM ttt
JOIN temp_ttt ON temp_ttt.vote = ttt.vote
ORDER BY ttt.vote DESC;
There an error was occured: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ';
CREATE TEMPORARY TABLE temp_ttt SELECT vote FROM ttt ORDER BY vote DESC LIMIT' at line 1".
So I thank you for idea :)
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Re: How to define TOP 5 records?
June 16, 2005 04:28AM
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