Re: Newbie Help
drop table if exists t;
create table t(hotel char(1),roomtype char(8));
insert into t values('a','single'),('a','double'),('b','single'),('c','suite');
select hotel
from t
where roomtype in('single','double')
group by hotel
having count(distinct roomtype) = 2;
+-------+
| hotel |
+-------+
| a |
+-------+
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Posted
December 09, 2012 12:33PM
Re: Newbie Help
December 09, 2012 01:03PM
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