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Re: "SELECT IN SELECT" problem in MySQL
Posted by: Peter Brawley
Date: September 22, 2014 09:48AM

> @list = SELECT
> rsa_policy_plan_lookup.rsa_lookup_id as lookup FROM rsa_policy_plan_lookup
> WHERE rsa_policy_plan_lookup.rsa_plan_id = 1;

If rsa_lookup_id contains list of values, fix the table design.

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Re: "SELECT IN SELECT" problem in MySQL
September 22, 2014 09:48AM


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