MySQL Forums
Forum List  »  Partitioning

PARTITION BY LIST "catch-all" partition
Posted by: Egor Ivkin
Date: January 20, 2010 03:25AM

Will there be a "catch-all" partition in PARTITION BY LIST?
Exemple from Oracle:

CREATE TABLE sales_list
(salesman_id NUMBER(5),
salesman_name VARCHAR2(30),
sales_state VARCHAR2(20),
sales_amount NUMBER(10),
sales_date DATE)
PARTITION BY LIST(sales_state)
(
PARTITION sales_west VALUES('California', 'Hawaii'),
PARTITION sales_east VALUES ('New York', 'Virginia', 'Florida'),
PARTITION sales_central VALUES('Texas', 'Illinois'),
PARTITION sales_other VALUES(DEFAULT)
);



Edited 1 time(s). Last edit at 01/21/2010 12:30AM by Egor Ivkin.

Options: ReplyQuote


Subject
Views
Written By
Posted
PARTITION BY LIST "catch-all" partition
5228
January 20, 2010 03:25AM


Sorry, you can't reply to this topic. It has been closed.

Content reproduced on this site is the property of the respective copyright holders. It is not reviewed in advance by Oracle and does not necessarily represent the opinion of Oracle or any other party.