Re: question about join query
thanks for all of the help.
for any who come looking, this is how i got the info that i needed:
$result4 = mysql_query("SELECT reportequipment.*,equipment.*
FROM reportequipment LEFT JOIN equipment ON reportequipment.equip = equipment.id
WHERE reportequipment.webid='$myid';
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October 19, 2009 07:11AM
Re: question about join query
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October 19, 2009 03:33PM
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