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Re: deadlock issue. Why is transaction waiting for an S lock when it already has an X lock?
Posted by: Richard Cook
Date: January 03, 2005 10:32PM

I just reread my post, and have a lot of typos. I apologize. Please let me clarify.

Also, I'm using version 4.0.22. The log is from a redhat box...

I'm seeing a deadlock which is confusing when I look at the log. It says here that Transaction 2 is waiting for a shared lock on the primary index of a table, one that it already has an X lock on.

Why is it waiting for an S lock, when it already has an X lock? Does it not realize this, or am I interpreting this incorrectly?

I'm looking through the source code, and see a function call lock_mode_stronger_or_eq() which I think would be used for this scenario, but I still haven't traced my way through the code...

Thanks for any help,
Rich

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deadlock issue. Why is transaction waiting for an S lock when it already has an X lock?
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Richard Cook
January 03, 2005 05:49PM
Re: deadlock issue. Why is transaction waiting for an S lock when it already has an X lock?
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Richard Cook
January 03, 2005 10:32PM
Re: deadlock issue. Why is transaction waiting for an S lock when it already has an X lock?
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Heikki Tuuri
January 10, 2005 05:00PM


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