Re: Display column contents in html table with PHP
Something like this?
<?php
mysql_connect('localhost', 'username', 'password');
mysql_select_db('mydatabase');
$sql = "SELECT categoria FROM categorias_tbl";
$result = mysql_query($sql);
//echo "<select name='categoria'>";
echo "<form action=\"#\">"; //Must have a form if you want to display inputs
echo "<table>"; //begin a table for your display
$cnt = 0; // <td> counter
while ($row = mysql_fetch_array($result)) {
if ($cnt % 3 == 0) { //even multiple of 3 <td>
echo "<tr>";
}
echo "<td><input type='checkbox' name=\"categoria\" value=\"{$row['categoria']}\" />{$row['categoria']}</td>";
++$cnt; // increment the <td> counter
}
while ($cnt % 3 != 0) {
// fill any leftover <td> to balance the table
echo "<td> </td>";
++$cnt;
}
echo "</table>"; // close the table
echo "</form>"; // close the form
?>
Good luck,
Barry.
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Re: Display column contents in html table with PHP
August 21, 2012 07:40PM
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