Re: error

[Barry Galbraith]

You need to add the error checking on the mysql_connect() call. That's what's failing.

$feedback = mysql_connect('localhost','user','password') or die(mysql_error());

Your error message is telling you that $feedback in the next line is expected to be of type resource, but it's null. So the mysql_connect() is failing. The error check will tell you why.

mysql_select_db($database_feedback, $feedback)or die(mysql_error());

$query_Recordset1 = "SELECT * FROM homeupdate ORDER BY id DESC";
$query_limit_Recordset1 = sprintf("%s LIMIT %d, %d", $query_Recordset1, $startRow_Recordset1, $maxRows_Recordset1);
$Recordset1 = mysql_query($query_limit_Recordset1, $feedback) or die(mysql_error());  // test for error here too
$row_Recordset1 = mysql_fetch_assoc($Recordset1);

Good luck,
Barry.