prepared statement syntax problem

[Dimitris Papageorgiou]

I have this query:
select u.name,u.lastname,t.user_type
from users u
join business_users b on u.user_id=b.crid
join buz_usertype t on b.bus_user_type=t.type_id
where u.lastname like 'P%';

It works on Netbeans console...but when run in a PHP script in a prepared statement it does not:

if($stmt = $connection->prepare('select u.name,u.lastname,t.user_type
from users u
join business_users b on u.user_id=b.crid
join buz_usertype t on b.bus_user_type=t.type_id
where u.lastname like=?%'))

I get this message...related to the syntax:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '=?%' at line 5,

What possible can be wrong here?