Get latest query based on two values but but only if value 1 is newer than value 2

[Don Pro]

I have a table (audit) like so

id | id_audit | id_booking
--------------------------
8 | 12345 | 10000
7 | 34567 | 10000
6 | 25608 | 10000
5 | 25864 | 10000
4 | 12345 | 10001
3 | 34567 | 10001
2 | 25864 | 10001
1 | 25608 | 10001

I want to return rows, one for each id_booking group but only if id_audit=25608 is newer than id_audit=25864. Newer is a higher id.

So for the records above, it would return only

id | id_audit | id_booking
--------------------------
6 | 25608 | 10000

Is there an efficient query to solve this? The index on the table is id_booking, id_audit

This works but is inefficient, takes long to run, and occasionally slows the server down whereby employees are affected.

SELECT a1.* FROM AUDIT a1
INNER JOIN
(
SELECT MAX(id) AS max_aud, id_audit, id_booking
FROM AUDIT
WHERE (id_audit='25608' OR id_audit='25864')
GROUP BY id_booking
) a2
ON a1.id_booking=a2.id_booking
AND a1.id=max_aud`
AND a1.id_audit='25608'