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XSL file formatting date
Posted by: angel rivero
Date: August 30, 2011 11:37PM

XSL file formatting

Hi there, I need your appreciated help.

I have problem with this files xsl, the problem is the output for the field date and number:

2011-05-13T21:50:00 instead of 13/05/2001 21:50:00
.00 instead of 0

This is the output in XML:
<xml xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882" xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882" xmlns:rs="urn:schemas-microsoft-com:rowset" xmlns:z="#RowsetSchema">
	<s:Schema id="RowsetSchema">
		<s:ElementType name="row" content="eltOnly" rs:CommandTimeout="30">

			<s:AttributeType name="myDates" rs:number="6" rs:nullable="true" rs:writeunknown="true">
				<s:datatype dt:type="dateTime" rs:dbtype="timestamp" dt:maxLength="16" rs:scale="0" rs:precision="19" rs:fixedlength="true"/>

			<s:AttributeType name="Net" rs:number="29" rs:nullable="true" rs:writeunknown="true">
				<s:datatype dt:type="number" rs:dbtype="numeric" dt:maxLength="19" rs:scale="2" rs:precision="10" rs:fixedlength="true"/>

			<s:extends type="rs:rowbase"/>

		<z:row myDates="2011-05-13T21:50:00" Net=".00" />


This output XML is generate with ASP code and saved in the csv format:
<!-- #include virtual="/_XML/" -->


filename = "titty.xml" 

Set xmlDoc = CreateObject("MSXML2.DOMDocument.4.0")
Set xslDoc = CreateObject("MSXML2.DOMDocument.4.0")



sql = "SELECT * FROM tbl_login" 
Set rs = objConn.Execute(sql) 

rs.Save xmlDoc, 1 

xmlDoc.Save Server.MapPath(filename)

Set rs = Nothing 



 Set oDOM = CreateObject("MSXML2.DOMDocument.4.0")
 oDOM.async = False 
 oDOM.Load Server.Mappath(filename)
 Set oXSL = CreateObject("MSXML2.DOMDocument.4.0") 
 oXSL.async = False 
 oXSL.Load Server.Mappath("Trasform_csv.xsl") 
 strTransform = oDOM.transformNode(oXSL) 
 Set fso = CreateObject("Scripting.FileSystemObject")
 strPath = Server.Mappath("testme.csv")
 Set file = fso.opentextfile(strPath, 2, True)
 file.write strTransform

 Set file = Nothing
 Set fso = Nothing
 Set oDOM = Nothing 
 Set oXML = Nothing 
 Set oXSL = Nothing 

The XSL file:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" 
	<xsl:output omit-xml-declaration="yes"/>
	<xsl:template match="/">
		<!-- show a header by looking Schema element -->
		<xsl:for-each select="/xml/s:Schema/s:ElementType/s:AttributeType">
			<xsl:value-of select="@name"/>
				<xsl:when test="position()!=last()">
  				    <!-- xls -->
					<!-- csv -->
		<!-- row data -->
		<xsl:for-each select="/xml/rs:data/z:row">
      <xsl:variable name="row" select="."/>
      <!-- for each column -->
			<xsl:for-each select="/xml/s:Schema/s:ElementType/s:AttributeType">
			   <!-- display each column if it exists -->
			  <xsl:variable name="columnName" select="@name"/>
				<!-- go through all columns and display something that matches-->
				<xsl:value-of select="$row/@*[name()=$columnName]" />
				<!--xsl:value-of select="translate($row/@*[name()=$columnName],'.',',')" /-->
				<xsl:if test="position()!=last()">
				    <!-- xls -->
					<!-- csv -->

I need another output in the XML file:
<z:row myDates="13/05/2001 21:50:00" Net="0.00" />
And in the CSV file:
13/05/2001 21:50:00, 0

Can you help me?
Thanks in advance.

Edited 1 time(s). Last edit at 08/30/2011 11:38PM by angel rivero.

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XSL file formatting date
August 30, 2011 11:37PM
September 01, 2011 10:14AM

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