Re: PreparedStatement syntax error
Posted by: Mark Matthews
Date: April 01, 2005 08:27PM

Chris Rickey wrote:
> This is interesting. I like using prepared
> statements, but this is problem is really
> frustrating me.
> If I attempt to use a prepared statement, I get
> the following error. However, if I change the
> code to include the value in the string instead of
> using substitution, it works. See the code
> below.
> Problem Code:
> sql = "select * from some_table where
> ";
> sql += "obj_key = ?";
> conn = this.getConnection();
> stmt = conn.prepareStatement(sql);
> stmt.setInt(1, 200);
> rs = stmt.executeQuery(sql);


Should be rs = stmt.executeQuery(); // i.e. no parameters

You're basically passing the query with the '?' in it to the _super_ interface implementation of executeQuery(String) in java.sql.Statement, which of course doesn't know what to do with placeholders.

I agree it's confusing, but it's also how inheritence in OO works ;)


Mark Matthews
Consulting Member Technical Staff - MySQL Enterprise Tools

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Re: PreparedStatement syntax error
April 01, 2005 08:27PM

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