Re: Show images from database

[Rick James]

> $out.="<img src=\"{$var['field_image_in_database']}\">
No.
src has to point to a file or a script.

$out.="<img src=\"filename\">

or
$out.="<img src=\"display.php?name={$var['field_image_in_database']}\">
And then you write display.php to take one argument (name) and fetch the image, then render it. Some of these may have examples:
http://forums.mysql.com/read.php?52,516761 (Output Image)
http://forums.mysql.com/read.php?52,423884 (variable not getting passed)
http://forums.mysql.com/read.php?10,398960 (How to retrieve images from a database)
http://forums.mysql.com/read.php?10,396307 (Database / Graphing)
http://forums.mysql.com/read.php?20,379180 (MySQL, Django, Python, html allllll in one! Help!!!)