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Estimating Index Size on Innodb Tables
Posted by: Paulo Victor Maluf Alves
Date: July 26, 2010 01:49PM

Dears,

I want to estimate an index size, based on innodb tables.


For instance:


Employees:
+------------+---------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+------------+---------------+------+-----+---------+-------+
| emp_no | int(11) | NO | PRI | NULL | |
| birth_date | date | NO | | NULL | |
| first_name | varchar(14) | NO | MUL | NULL | |
| last_name | varchar(16) | NO | | NULL | |
| gender | enum('M','F') | NO | | NULL | |
| hire_date | date | NO | | NULL | |
+------------+---------------+------+-----+---------+-------+

select count(1) from employees;
+----------+
| count(1) |
+----------+
| 300024 |
+----------+

I try:

SELECT ROUND(AVG(LENGTH(first_name)),2) FROM employees;
+----------------------------------+
| ROUND(AVG(LENGTH(first_name)),2) |
+----------------------------------+
| 6.22 |
+----------------------------------+

So:
(6.22 * 300024)/1024/1024 = 1.77 MB


Whats wrong?


if I create an index, it is at least 4x greater:


mysql> create index first_idx01 on employees(first_name);

mysql> SELECT ROUND(index_length/1024/1024,2) as total_index_size_mb FROM information_schema.TABLES WHERE table_name = 'employees';
+---------------------+
| total_index_size_mb |
+---------------------+
| 9.52 |
+---------------------+


Thanks.

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